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Who Won: A.J. Green or Johnathan Joseph

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One of the more anticipated matchups of the Bengals Week 14 game against the Kansas City Chiefs was former Bengals cornerback Johnathan Joseph against Bengals rookie wide receiver A.J. Green.

Joseph left the Bengals in the offseason after five years and signed with the Houston Texans. He is the team's top cornerback and is having one of the best years of his career. Green replaced Chad Ochocinco as the Bengals' No. 1 receiver and has been nothing short of amazing so far this year. He's in the conversation for Offensive Rookie of the Year and has either scored a touchdown or had more than 80 yards receiving in every game but two.

So, who won that matchup?

Quarterback Andy Dalton targeted Green seven times on Sunday. Green caught five of the seven passes thrown to him. Those five catches went for 59 yards including one 36-yard catch. Green had 17 total yards after catches which averaged out to be 3.4 yards after each catch.

Joseph covered Green throughout the entire game. Green's 36-yard catch was the second longest play that Joseph has given up so far this season. He did have two passes defensed (likely the two that Green didn't catch) and Dalton had a 89.1 passer rating when throwing to a receiver Joseph was covering (which was Green except for one play), which is the third highest passer rating that he has allowed so far this season.

Green didn't score a touchdown and this was the only time, other than the team's Week 3 game against the 49ers, in which he played that he was held to less than 80 yards without a touchdown. However, Green's 59 yards is the second most amount of yards that Joseph has allowed one receiver to accumulate while he was covering him so far this season.

Considering all of this, who do you think won the matchup between Green and Joseph?