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Justin Herbert surpasses Joe Burrow as favorite for Offensive Rookie of the Year

With seven touchdowns in his last two games, Herbert has the numbers to support his case over the Bengals’ rookie QB.

Los Angeles Chargers v Tampa Bay Buccaneers Photo by James Gilbert/Getty Images

Despite a rough debut, Joe Burrow has lived up to Cincinnati’s every expectation. The No. 1 overall pick has led the team to a win in their first five games, a feat that Andy Dalton wasn’t able to do a year ago.

Even with a broken and oftentimes under-performing offensive line, Burrow has still been able to rack up 300 or more yards in three of his five appearances.

With six touchdowns and three interceptions on the year, Burrow’s Bengals are 1-3-1, fourth place in the AFC North.

One of three quarterbacks picked in the top ten, Burrow was joined by Miami’s Tua Tagovailoa and Los Angeles’ Justin Herbert. Tua has yet to see much time on the field as Ryan Fitzpatrick is leading the charge in Miami.

As for Los Angeles, they too had a veteran quarterback kick off the season, but Tyrod Taylor suffered a team-inflicted injury which kept him out a few games, enough time for Herbert to steal the show.

Having an awing performance on Monday Night Football, Herbert has overtaken Burrow as the favorite for Offensive Rookie of the Year.

According to BetOnline via Sports Illustrated’s James Rapien, Herbert has 5/1 odds while Burrow’s have dropped to 5/4. Cowboys’ receiver CeeDee Lamb comes in at No. 3 with Chase Claypool, Clyde Edwards-Helaire, and Jonathan Taylor following him.

As for Herbert, he has nine touchdowns and three inceptions to his name.

With seven combined touchdowns in the last two weeks, the 6-foot-6 rookie has been able to show off his absolute cannon of an arm. Collecting over 260 yards in each of his four performances, starting in Week 2, Herbert has been incredible.

That said, it’s still early in the season, and OROY is still anyones to win.